Y(4y-3)=4(y^2+6)

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Solution for Y(4y-3)=4(y^2+6) equation: 


Simplifying
Y(4y + -3) = 4(y2 + 6)

Reorder the terms:
Y(-3 + 4y) = 4(y2 + 6)
(-3 * Y + 4y * Y) = 4(y2 + 6)
(-3Y + 4yY) = 4(y2 + 6)

Reorder the terms:
-3Y + 4yY = 4(6 + y2)
-3Y + 4yY = (6 * 4 + y2 * 4)
-3Y + 4yY = (24 + 4y2)

Solving
-3Y + 4yY = 24 + 4y2

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Reorder the terms:
-24 + -3Y + 4yY + -4y2 = 24 + 4y2 + -24 + -4y2

Reorder the terms:
-24 + -3Y + 4yY + -4y2 = 24 + -24 + 4y2 + -4y2

Combine like terms: 24 + -24 = 0
-24 + -3Y + 4yY + -4y2 = 0 + 4y2 + -4y2
-24 + -3Y + 4yY + -4y2 = 4y2 + -4y2

Combine like terms: 4y2 + -4y2 = 0
-24 + -3Y + 4yY + -4y2 = 0

The solution to this equation could not be determined.

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